3x^2+27x+56=0

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Solution for 3x^2+27x+56=0 equation: 



3x^2+27x+56=0

a = 3; b = 27; c = +56;
Δ = b2-4ac
Δ = 272-4·3·56
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-\sqrt{57}}{2*3}=\frac{-27-\sqrt{57}}{6}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+\sqrt{57}}{2*3}=\frac{-27+\sqrt{57}}{6}
$

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